3.606 \(\int (d+e x^2)^4 (a+b \sinh ^{-1}(c x)) \, dx\)

Optimal. Leaf size=312 \[ d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-\frac {4 b e^3 \left (c^2 x^2+1\right )^{7/2} \left (9 c^2 d-7 e\right )}{441 c^9}-\frac {b e^4 \left (c^2 x^2+1\right )^{9/2}}{81 c^9}-\frac {2 b e^2 \left (c^2 x^2+1\right )^{5/2} \left (63 c^4 d^2-90 c^2 d e+35 e^2\right )}{525 c^9}-\frac {4 b e \left (c^2 x^2+1\right )^{3/2} \left (105 c^6 d^3-189 c^4 d^2 e+135 c^2 d e^2-35 e^3\right )}{945 c^9}-\frac {b \sqrt {c^2 x^2+1} \left (315 c^8 d^4-420 c^6 d^3 e+378 c^4 d^2 e^2-180 c^2 d e^3+35 e^4\right )}{315 c^9} \]

[Out]

-4/945*b*e*(105*c^6*d^3-189*c^4*d^2*e+135*c^2*d*e^2-35*e^3)*(c^2*x^2+1)^(3/2)/c^9-2/525*b*e^2*(63*c^4*d^2-90*c
^2*d*e+35*e^2)*(c^2*x^2+1)^(5/2)/c^9-4/441*b*(9*c^2*d-7*e)*e^3*(c^2*x^2+1)^(7/2)/c^9-1/81*b*e^4*(c^2*x^2+1)^(9
/2)/c^9+d^4*x*(a+b*arcsinh(c*x))+4/3*d^3*e*x^3*(a+b*arcsinh(c*x))+6/5*d^2*e^2*x^5*(a+b*arcsinh(c*x))+4/7*d*e^3
*x^7*(a+b*arcsinh(c*x))+1/9*e^4*x^9*(a+b*arcsinh(c*x))-1/315*b*(315*c^8*d^4-420*c^6*d^3*e+378*c^4*d^2*e^2-180*
c^2*d*e^3+35*e^4)*(c^2*x^2+1)^(1/2)/c^9

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Rubi [A]  time = 0.35, antiderivative size = 312, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {194, 5704, 12, 1799, 1850} \[ \frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-\frac {2 b e^2 \left (c^2 x^2+1\right )^{5/2} \left (63 c^4 d^2-90 c^2 d e+35 e^2\right )}{525 c^9}-\frac {4 b e \left (c^2 x^2+1\right )^{3/2} \left (-189 c^4 d^2 e+105 c^6 d^3+135 c^2 d e^2-35 e^3\right )}{945 c^9}-\frac {b \sqrt {c^2 x^2+1} \left (378 c^4 d^2 e^2-420 c^6 d^3 e+315 c^8 d^4-180 c^2 d e^3+35 e^4\right )}{315 c^9}-\frac {4 b e^3 \left (c^2 x^2+1\right )^{7/2} \left (9 c^2 d-7 e\right )}{441 c^9}-\frac {b e^4 \left (c^2 x^2+1\right )^{9/2}}{81 c^9} \]

Antiderivative was successfully verified.

[In]

Int[(d + e*x^2)^4*(a + b*ArcSinh[c*x]),x]

[Out]

-(b*(315*c^8*d^4 - 420*c^6*d^3*e + 378*c^4*d^2*e^2 - 180*c^2*d*e^3 + 35*e^4)*Sqrt[1 + c^2*x^2])/(315*c^9) - (4
*b*e*(105*c^6*d^3 - 189*c^4*d^2*e + 135*c^2*d*e^2 - 35*e^3)*(1 + c^2*x^2)^(3/2))/(945*c^9) - (2*b*e^2*(63*c^4*
d^2 - 90*c^2*d*e + 35*e^2)*(1 + c^2*x^2)^(5/2))/(525*c^9) - (4*b*(9*c^2*d - 7*e)*e^3*(1 + c^2*x^2)^(7/2))/(441
*c^9) - (b*e^4*(1 + c^2*x^2)^(9/2))/(81*c^9) + d^4*x*(a + b*ArcSinh[c*x]) + (4*d^3*e*x^3*(a + b*ArcSinh[c*x]))
/3 + (6*d^2*e^2*x^5*(a + b*ArcSinh[c*x]))/5 + (4*d*e^3*x^7*(a + b*ArcSinh[c*x]))/7 + (e^4*x^9*(a + b*ArcSinh[c
*x]))/9

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 194

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[ExpandIntegrand[(a + b*x^n)^p, x], x] /; FreeQ[{a, b}, x]
&& IGtQ[n, 0] && IGtQ[p, 0]

Rule 1799

Int[(Pq_)*(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[x^((m - 1)/2)*SubstFor[x^2,
Pq, x]*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, p}, x] && PolyQ[Pq, x^2] && IntegerQ[(m - 1)/2]

Rule 1850

Int[(Pq_)*((a_) + (b_.)*(x_)^(n_.))^(p_.), x_Symbol] :> Int[ExpandIntegrand[Pq*(a + b*x^n)^p, x], x] /; FreeQ[
{a, b, n}, x] && PolyQ[Pq, x] && (IGtQ[p, 0] || EqQ[n, 1])

Rule 5704

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u = IntHide[(d + e*x^2
)^p, x]}, Dist[a + b*ArcSinh[c*x], u, x] - Dist[b*c, Int[SimplifyIntegrand[u/Sqrt[1 + c^2*x^2], x], x], x]] /;
FreeQ[{a, b, c, d, e}, x] && NeQ[e, c^2*d] && (IGtQ[p, 0] || ILtQ[p + 1/2, 0])

Rubi steps

\begin {align*} \int \left (d+e x^2\right )^4 \left (a+b \sinh ^{-1}(c x)\right ) \, dx &=d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-(b c) \int \frac {x \left (315 d^4+420 d^3 e x^2+378 d^2 e^2 x^4+180 d e^3 x^6+35 e^4 x^8\right )}{315 \sqrt {1+c^2 x^2}} \, dx\\ &=d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{315} (b c) \int \frac {x \left (315 d^4+420 d^3 e x^2+378 d^2 e^2 x^4+180 d e^3 x^6+35 e^4 x^8\right )}{\sqrt {1+c^2 x^2}} \, dx\\ &=d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{630} (b c) \operatorname {Subst}\left (\int \frac {315 d^4+420 d^3 e x+378 d^2 e^2 x^2+180 d e^3 x^3+35 e^4 x^4}{\sqrt {1+c^2 x}} \, dx,x,x^2\right )\\ &=d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )-\frac {1}{630} (b c) \operatorname {Subst}\left (\int \left (\frac {315 c^8 d^4-420 c^6 d^3 e+378 c^4 d^2 e^2-180 c^2 d e^3+35 e^4}{c^8 \sqrt {1+c^2 x}}+\frac {4 e \left (105 c^6 d^3-189 c^4 d^2 e+135 c^2 d e^2-35 e^3\right ) \sqrt {1+c^2 x}}{c^8}+\frac {6 e^2 \left (63 c^4 d^2-90 c^2 d e+35 e^2\right ) \left (1+c^2 x\right )^{3/2}}{c^8}+\frac {20 \left (9 c^2 d-7 e\right ) e^3 \left (1+c^2 x\right )^{5/2}}{c^8}+\frac {35 e^4 \left (1+c^2 x\right )^{7/2}}{c^8}\right ) \, dx,x,x^2\right )\\ &=-\frac {b \left (315 c^8 d^4-420 c^6 d^3 e+378 c^4 d^2 e^2-180 c^2 d e^3+35 e^4\right ) \sqrt {1+c^2 x^2}}{315 c^9}-\frac {4 b e \left (105 c^6 d^3-189 c^4 d^2 e+135 c^2 d e^2-35 e^3\right ) \left (1+c^2 x^2\right )^{3/2}}{945 c^9}-\frac {2 b e^2 \left (63 c^4 d^2-90 c^2 d e+35 e^2\right ) \left (1+c^2 x^2\right )^{5/2}}{525 c^9}-\frac {4 b \left (9 c^2 d-7 e\right ) e^3 \left (1+c^2 x^2\right )^{7/2}}{441 c^9}-\frac {b e^4 \left (1+c^2 x^2\right )^{9/2}}{81 c^9}+d^4 x \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{3} d^3 e x^3 \left (a+b \sinh ^{-1}(c x)\right )+\frac {6}{5} d^2 e^2 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {4}{7} d e^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{9} e^4 x^9 \left (a+b \sinh ^{-1}(c x)\right )\\ \end {align*}

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Mathematica [A]  time = 0.36, size = 260, normalized size = 0.83 \[ \frac {315 a x \left (315 d^4+420 d^3 e x^2+378 d^2 e^2 x^4+180 d e^3 x^6+35 e^4 x^8\right )-\frac {b \sqrt {c^2 x^2+1} \left (c^8 \left (99225 d^4+44100 d^3 e x^2+23814 d^2 e^2 x^4+8100 d e^3 x^6+1225 e^4 x^8\right )-8 c^6 e \left (11025 d^3+3969 d^2 e x^2+1215 d e^2 x^4+175 e^3 x^6\right )+48 c^4 e^2 \left (1323 d^2+270 d e x^2+35 e^2 x^4\right )-320 c^2 e^3 \left (81 d+7 e x^2\right )+4480 e^4\right )}{c^9}+315 b x \sinh ^{-1}(c x) \left (315 d^4+420 d^3 e x^2+378 d^2 e^2 x^4+180 d e^3 x^6+35 e^4 x^8\right )}{99225} \]

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x^2)^4*(a + b*ArcSinh[c*x]),x]

[Out]

(315*a*x*(315*d^4 + 420*d^3*e*x^2 + 378*d^2*e^2*x^4 + 180*d*e^3*x^6 + 35*e^4*x^8) - (b*Sqrt[1 + c^2*x^2]*(4480
*e^4 - 320*c^2*e^3*(81*d + 7*e*x^2) + 48*c^4*e^2*(1323*d^2 + 270*d*e*x^2 + 35*e^2*x^4) - 8*c^6*e*(11025*d^3 +
3969*d^2*e*x^2 + 1215*d*e^2*x^4 + 175*e^3*x^6) + c^8*(99225*d^4 + 44100*d^3*e*x^2 + 23814*d^2*e^2*x^4 + 8100*d
*e^3*x^6 + 1225*e^4*x^8)))/c^9 + 315*b*x*(315*d^4 + 420*d^3*e*x^2 + 378*d^2*e^2*x^4 + 180*d*e^3*x^6 + 35*e^4*x
^8)*ArcSinh[c*x])/99225

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fricas [A]  time = 0.61, size = 333, normalized size = 1.07 \[ \frac {11025 \, a c^{9} e^{4} x^{9} + 56700 \, a c^{9} d e^{3} x^{7} + 119070 \, a c^{9} d^{2} e^{2} x^{5} + 132300 \, a c^{9} d^{3} e x^{3} + 99225 \, a c^{9} d^{4} x + 315 \, {\left (35 \, b c^{9} e^{4} x^{9} + 180 \, b c^{9} d e^{3} x^{7} + 378 \, b c^{9} d^{2} e^{2} x^{5} + 420 \, b c^{9} d^{3} e x^{3} + 315 \, b c^{9} d^{4} x\right )} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) - {\left (1225 \, b c^{8} e^{4} x^{8} + 99225 \, b c^{8} d^{4} - 88200 \, b c^{6} d^{3} e + 63504 \, b c^{4} d^{2} e^{2} - 25920 \, b c^{2} d e^{3} + 100 \, {\left (81 \, b c^{8} d e^{3} - 14 \, b c^{6} e^{4}\right )} x^{6} + 4480 \, b e^{4} + 6 \, {\left (3969 \, b c^{8} d^{2} e^{2} - 1620 \, b c^{6} d e^{3} + 280 \, b c^{4} e^{4}\right )} x^{4} + 4 \, {\left (11025 \, b c^{8} d^{3} e - 7938 \, b c^{6} d^{2} e^{2} + 3240 \, b c^{4} d e^{3} - 560 \, b c^{2} e^{4}\right )} x^{2}\right )} \sqrt {c^{2} x^{2} + 1}}{99225 \, c^{9}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^4*(a+b*arcsinh(c*x)),x, algorithm="fricas")

[Out]

1/99225*(11025*a*c^9*e^4*x^9 + 56700*a*c^9*d*e^3*x^7 + 119070*a*c^9*d^2*e^2*x^5 + 132300*a*c^9*d^3*e*x^3 + 992
25*a*c^9*d^4*x + 315*(35*b*c^9*e^4*x^9 + 180*b*c^9*d*e^3*x^7 + 378*b*c^9*d^2*e^2*x^5 + 420*b*c^9*d^3*e*x^3 + 3
15*b*c^9*d^4*x)*log(c*x + sqrt(c^2*x^2 + 1)) - (1225*b*c^8*e^4*x^8 + 99225*b*c^8*d^4 - 88200*b*c^6*d^3*e + 635
04*b*c^4*d^2*e^2 - 25920*b*c^2*d*e^3 + 100*(81*b*c^8*d*e^3 - 14*b*c^6*e^4)*x^6 + 4480*b*e^4 + 6*(3969*b*c^8*d^
2*e^2 - 1620*b*c^6*d*e^3 + 280*b*c^4*e^4)*x^4 + 4*(11025*b*c^8*d^3*e - 7938*b*c^6*d^2*e^2 + 3240*b*c^4*d*e^3 -
560*b*c^2*e^4)*x^2)*sqrt(c^2*x^2 + 1))/c^9

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^4*(a+b*arcsinh(c*x)),x, algorithm="giac")

[Out]

Exception raised: RuntimeError >> An error occurred running a Giac command:INPUT:sage2OUTPUT:sym2poly/r2sym(co
nst gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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maple [A]  time = 0.02, size = 451, normalized size = 1.45 \[ \frac {\frac {a \left (\frac {1}{9} e^{4} c^{9} x^{9}+\frac {4}{7} c^{9} d \,e^{3} x^{7}+\frac {6}{5} c^{9} d^{2} e^{2} x^{5}+\frac {4}{3} c^{9} d^{3} e \,x^{3}+c^{9} d^{4} x \right )}{c^{8}}+\frac {b \left (\frac {\arcsinh \left (c x \right ) e^{4} c^{9} x^{9}}{9}+\frac {4 \arcsinh \left (c x \right ) c^{9} d \,e^{3} x^{7}}{7}+\frac {6 \arcsinh \left (c x \right ) c^{9} d^{2} e^{2} x^{5}}{5}+\frac {4 \arcsinh \left (c x \right ) c^{9} d^{3} e \,x^{3}}{3}+\arcsinh \left (c x \right ) c^{9} d^{4} x -\frac {e^{4} \left (\frac {c^{8} x^{8} \sqrt {c^{2} x^{2}+1}}{9}-\frac {8 c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{63}+\frac {16 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{105}-\frac {64 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{315}+\frac {128 \sqrt {c^{2} x^{2}+1}}{315}\right )}{9}-\frac {4 c^{2} d \,e^{3} \left (\frac {c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{7}-\frac {6 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{35}+\frac {8 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{35}-\frac {16 \sqrt {c^{2} x^{2}+1}}{35}\right )}{7}-\frac {6 c^{4} d^{2} e^{2} \left (\frac {c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{5}-\frac {4 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{15}+\frac {8 \sqrt {c^{2} x^{2}+1}}{15}\right )}{5}-\frac {4 c^{6} d^{3} e \left (\frac {c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{3}-\frac {2 \sqrt {c^{2} x^{2}+1}}{3}\right )}{3}-c^{8} d^{4} \sqrt {c^{2} x^{2}+1}\right )}{c^{8}}}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x^2+d)^4*(a+b*arcsinh(c*x)),x)

[Out]

1/c*(a/c^8*(1/9*e^4*c^9*x^9+4/7*c^9*d*e^3*x^7+6/5*c^9*d^2*e^2*x^5+4/3*c^9*d^3*e*x^3+c^9*d^4*x)+b/c^8*(1/9*arcs
inh(c*x)*e^4*c^9*x^9+4/7*arcsinh(c*x)*c^9*d*e^3*x^7+6/5*arcsinh(c*x)*c^9*d^2*e^2*x^5+4/3*arcsinh(c*x)*c^9*d^3*
e*x^3+arcsinh(c*x)*c^9*d^4*x-1/9*e^4*(1/9*c^8*x^8*(c^2*x^2+1)^(1/2)-8/63*c^6*x^6*(c^2*x^2+1)^(1/2)+16/105*c^4*
x^4*(c^2*x^2+1)^(1/2)-64/315*c^2*x^2*(c^2*x^2+1)^(1/2)+128/315*(c^2*x^2+1)^(1/2))-4/7*c^2*d*e^3*(1/7*c^6*x^6*(
c^2*x^2+1)^(1/2)-6/35*c^4*x^4*(c^2*x^2+1)^(1/2)+8/35*c^2*x^2*(c^2*x^2+1)^(1/2)-16/35*(c^2*x^2+1)^(1/2))-6/5*c^
4*d^2*e^2*(1/5*c^4*x^4*(c^2*x^2+1)^(1/2)-4/15*c^2*x^2*(c^2*x^2+1)^(1/2)+8/15*(c^2*x^2+1)^(1/2))-4/3*c^6*d^3*e*
(1/3*c^2*x^2*(c^2*x^2+1)^(1/2)-2/3*(c^2*x^2+1)^(1/2))-c^8*d^4*(c^2*x^2+1)^(1/2)))

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maxima [A]  time = 0.41, size = 415, normalized size = 1.33 \[ \frac {1}{9} \, a e^{4} x^{9} + \frac {4}{7} \, a d e^{3} x^{7} + \frac {6}{5} \, a d^{2} e^{2} x^{5} + \frac {4}{3} \, a d^{3} e x^{3} + \frac {4}{9} \, {\left (3 \, x^{3} \operatorname {arsinh}\left (c x\right ) - c {\left (\frac {\sqrt {c^{2} x^{2} + 1} x^{2}}{c^{2}} - \frac {2 \, \sqrt {c^{2} x^{2} + 1}}{c^{4}}\right )}\right )} b d^{3} e + \frac {2}{25} \, {\left (15 \, x^{5} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {3 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{2}} - \frac {4 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1}}{c^{6}}\right )} c\right )} b d^{2} e^{2} + \frac {4}{245} \, {\left (35 \, x^{7} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {5 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{2}} - \frac {6 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{6}} - \frac {16 \, \sqrt {c^{2} x^{2} + 1}}{c^{8}}\right )} c\right )} b d e^{3} + \frac {1}{2835} \, {\left (315 \, x^{9} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {35 \, \sqrt {c^{2} x^{2} + 1} x^{8}}{c^{2}} - \frac {40 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{4}} + \frac {48 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{6}} - \frac {64 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{8}} + \frac {128 \, \sqrt {c^{2} x^{2} + 1}}{c^{10}}\right )} c\right )} b e^{4} + a d^{4} x + \frac {{\left (c x \operatorname {arsinh}\left (c x\right ) - \sqrt {c^{2} x^{2} + 1}\right )} b d^{4}}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^4*(a+b*arcsinh(c*x)),x, algorithm="maxima")

[Out]

1/9*a*e^4*x^9 + 4/7*a*d*e^3*x^7 + 6/5*a*d^2*e^2*x^5 + 4/3*a*d^3*e*x^3 + 4/9*(3*x^3*arcsinh(c*x) - c*(sqrt(c^2*
x^2 + 1)*x^2/c^2 - 2*sqrt(c^2*x^2 + 1)/c^4))*b*d^3*e + 2/25*(15*x^5*arcsinh(c*x) - (3*sqrt(c^2*x^2 + 1)*x^4/c^
2 - 4*sqrt(c^2*x^2 + 1)*x^2/c^4 + 8*sqrt(c^2*x^2 + 1)/c^6)*c)*b*d^2*e^2 + 4/245*(35*x^7*arcsinh(c*x) - (5*sqrt
(c^2*x^2 + 1)*x^6/c^2 - 6*sqrt(c^2*x^2 + 1)*x^4/c^4 + 8*sqrt(c^2*x^2 + 1)*x^2/c^6 - 16*sqrt(c^2*x^2 + 1)/c^8)*
c)*b*d*e^3 + 1/2835*(315*x^9*arcsinh(c*x) - (35*sqrt(c^2*x^2 + 1)*x^8/c^2 - 40*sqrt(c^2*x^2 + 1)*x^6/c^4 + 48*
sqrt(c^2*x^2 + 1)*x^4/c^6 - 64*sqrt(c^2*x^2 + 1)*x^2/c^8 + 128*sqrt(c^2*x^2 + 1)/c^10)*c)*b*e^4 + a*d^4*x + (c
*x*arcsinh(c*x) - sqrt(c^2*x^2 + 1))*b*d^4/c

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (e\,x^2+d\right )}^4 \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*asinh(c*x))*(d + e*x^2)^4,x)

[Out]

int((a + b*asinh(c*x))*(d + e*x^2)^4, x)

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sympy [A]  time = 18.00, size = 593, normalized size = 1.90 \[ \begin {cases} a d^{4} x + \frac {4 a d^{3} e x^{3}}{3} + \frac {6 a d^{2} e^{2} x^{5}}{5} + \frac {4 a d e^{3} x^{7}}{7} + \frac {a e^{4} x^{9}}{9} + b d^{4} x \operatorname {asinh}{\left (c x \right )} + \frac {4 b d^{3} e x^{3} \operatorname {asinh}{\left (c x \right )}}{3} + \frac {6 b d^{2} e^{2} x^{5} \operatorname {asinh}{\left (c x \right )}}{5} + \frac {4 b d e^{3} x^{7} \operatorname {asinh}{\left (c x \right )}}{7} + \frac {b e^{4} x^{9} \operatorname {asinh}{\left (c x \right )}}{9} - \frac {b d^{4} \sqrt {c^{2} x^{2} + 1}}{c} - \frac {4 b d^{3} e x^{2} \sqrt {c^{2} x^{2} + 1}}{9 c} - \frac {6 b d^{2} e^{2} x^{4} \sqrt {c^{2} x^{2} + 1}}{25 c} - \frac {4 b d e^{3} x^{6} \sqrt {c^{2} x^{2} + 1}}{49 c} - \frac {b e^{4} x^{8} \sqrt {c^{2} x^{2} + 1}}{81 c} + \frac {8 b d^{3} e \sqrt {c^{2} x^{2} + 1}}{9 c^{3}} + \frac {8 b d^{2} e^{2} x^{2} \sqrt {c^{2} x^{2} + 1}}{25 c^{3}} + \frac {24 b d e^{3} x^{4} \sqrt {c^{2} x^{2} + 1}}{245 c^{3}} + \frac {8 b e^{4} x^{6} \sqrt {c^{2} x^{2} + 1}}{567 c^{3}} - \frac {16 b d^{2} e^{2} \sqrt {c^{2} x^{2} + 1}}{25 c^{5}} - \frac {32 b d e^{3} x^{2} \sqrt {c^{2} x^{2} + 1}}{245 c^{5}} - \frac {16 b e^{4} x^{4} \sqrt {c^{2} x^{2} + 1}}{945 c^{5}} + \frac {64 b d e^{3} \sqrt {c^{2} x^{2} + 1}}{245 c^{7}} + \frac {64 b e^{4} x^{2} \sqrt {c^{2} x^{2} + 1}}{2835 c^{7}} - \frac {128 b e^{4} \sqrt {c^{2} x^{2} + 1}}{2835 c^{9}} & \text {for}\: c \neq 0 \\a \left (d^{4} x + \frac {4 d^{3} e x^{3}}{3} + \frac {6 d^{2} e^{2} x^{5}}{5} + \frac {4 d e^{3} x^{7}}{7} + \frac {e^{4} x^{9}}{9}\right ) & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x**2+d)**4*(a+b*asinh(c*x)),x)

[Out]

Piecewise((a*d**4*x + 4*a*d**3*e*x**3/3 + 6*a*d**2*e**2*x**5/5 + 4*a*d*e**3*x**7/7 + a*e**4*x**9/9 + b*d**4*x*
asinh(c*x) + 4*b*d**3*e*x**3*asinh(c*x)/3 + 6*b*d**2*e**2*x**5*asinh(c*x)/5 + 4*b*d*e**3*x**7*asinh(c*x)/7 + b
*e**4*x**9*asinh(c*x)/9 - b*d**4*sqrt(c**2*x**2 + 1)/c - 4*b*d**3*e*x**2*sqrt(c**2*x**2 + 1)/(9*c) - 6*b*d**2*
e**2*x**4*sqrt(c**2*x**2 + 1)/(25*c) - 4*b*d*e**3*x**6*sqrt(c**2*x**2 + 1)/(49*c) - b*e**4*x**8*sqrt(c**2*x**2
+ 1)/(81*c) + 8*b*d**3*e*sqrt(c**2*x**2 + 1)/(9*c**3) + 8*b*d**2*e**2*x**2*sqrt(c**2*x**2 + 1)/(25*c**3) + 24
*b*d*e**3*x**4*sqrt(c**2*x**2 + 1)/(245*c**3) + 8*b*e**4*x**6*sqrt(c**2*x**2 + 1)/(567*c**3) - 16*b*d**2*e**2*
sqrt(c**2*x**2 + 1)/(25*c**5) - 32*b*d*e**3*x**2*sqrt(c**2*x**2 + 1)/(245*c**5) - 16*b*e**4*x**4*sqrt(c**2*x**
2 + 1)/(945*c**5) + 64*b*d*e**3*sqrt(c**2*x**2 + 1)/(245*c**7) + 64*b*e**4*x**2*sqrt(c**2*x**2 + 1)/(2835*c**7
) - 128*b*e**4*sqrt(c**2*x**2 + 1)/(2835*c**9), Ne(c, 0)), (a*(d**4*x + 4*d**3*e*x**3/3 + 6*d**2*e**2*x**5/5 +
4*d*e**3*x**7/7 + e**4*x**9/9), True))

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